1. X-2 = 02. X +3=03. x(x-4) = 04. (x-4)(x - 3) = 05. x²(x - 9)(2x + 1) = 0
1. 1. X-2 = 02. X +3=03. x(x-4) = 04. (x-4)(x - 3) = 05. x²(x - 9)(2x + 1) = 0
1.) The answer is 2
SOLUTION:→ x - 2= 0
Move the constant to the right-hand side by adding its opposite to both sides
→ x - 2 + 2= 0 + 2
Simplify
→ x= 2
2.) The answer is -3
SOLUTION:→ x + 3= 0
Move the constant to the right-hand side by adding its opposite to both sides
→ x + 3 - 3= 0 - 3
Simplify
→ x= -3
3.) The answer is x= 0 or x= 4
SOLUTION:→ x(x - 4)= 0
Separate into possible cases
→ x= 0 ; x - 4= 0
Solve the equation for x
→ x= 0 ; x= 4
4.) The answer is x= 4 or x= 3
SOLUTION:→ (x - 4) (x - 3) = 0
Separate into possible cases
→ x - 4= 0 ; x - 3= 0
Solve the equation for x
→ x= 4 ; x= 3
5.) The answer is x= 0 or x= 9 or x= - 1/2
SOLUTION:→ x²(x - 9) (2x + 1) = 0
Separate into possible cases
→ x²= 0 ; x - 9= 0 ; 2x + 1= 0
Solve the equation for x
→ x= 0 ; x= 9 ; x= - 1/2
2. 1. X-2 = 02. X +3=03. x(x-4)=04. (x-4)(x-3) = 05. x(x-9)(2x + 115
Answer:
1. 2
2. -3
3. 2
4. 4 & 3
5.3 &
3. 1. 3 x (x + 2) = 0 2. 5x(x-3) = 0 3. (x +3)(×+4)=0 4. (x + 5) (x-6)=0
Answer:
1. 3x² + 6x = 0
2. 5x² - 15x = 0
3. x² + 7x + 12 = 0
4. x² + 11x + 30 = 0
4. Determine the real root(s) of each equation. 1. x + 4 = 0 2. X-3 = 0 3. x(x - 1) = 0 4. (x + 2)(x + 3) = 0 5. (x + 4)(x - 3) = 0 with solutions
Answer:
Sana makatulong
stay safe❤❤
5. are the solutions of x+4=0 and x-3=0 the same as the solutions of (x+4)(x-3)=0?
Step-by-step explanation:
(x+4)(x-3)
x + 4
x x - 3
------------
3x -12
x^ +4x
--------------
x^ +12 -12
Answer: x^ +12 -12
6. Determine the real roots of each equation1. x-2=02.x+3=03.x(x-4)=04.(x+1)(x-3)=05. x²+x-2=0
Answer:
1. x=2
2. x=-3
3. x= 0 & x=4
4. x=-1 & x=3
5. x=-2 & x=1
7. Activity 4: Determine the real root(s) of each equation.1. x - 2 = 02. X + 3 = 03. x(x-4) = 04. (x-4)(x-3) = 05. x²(x - 9)(2x + 1) = 0with solution
1. x-2 = 0
x = 0+2
x = 2
2. x+3 = 0
x = 0 -3
x = -3
3. x(x-4) =0
x =0
x-4 = 0
x = 0 +4
x = 4
4. (x-4)(x-3) = 0
x-4 = 0
x = 0+4
x = 4
x-3 = 0
x = 0+3
x = 3
5. x^2(x-9)(2x+1) = 0
x^2 = 0 take their square root
x = 0
x-9 =0
x = 0 + 9
x = 9
2x +1 = 0
2x = 0 -1
2x = -1 divide both side by 2
x = -1/2
8. find the root of the following polynomials equation applying the zero-product property 1.(x-3)(x+2)=0 2.x(x-4)=0 3.(x+3)(x-2)(x+1)=0 4.(x+4)²(x-1)³=0 5.x(x-3)⁴(x+6)²=0
Answer:
1.X²-x-6
2.x²-4x
3.x³+2x²-5×-6
4.x⁴+6x³+ײ-24×+16
5.??
9. Give the Degree and number of roots1. (x –3) (x+5) = 0 2. x–13= 03. (x +4) (x - 1)³= 0 4. (x–1)²= 05. (x + 2) (x +1) (x–3= 06.(x+5)²(x–2)³(x+1)=07.(x–3)³=0
Answer:
Step-by-step explanation:
pa brainliest po tapos install nyo po ung photi math
10. equation. x²+4x+3=0 answer:a=1 b=4 c=3b²-4ac(4)²-4(1)(3)16-124by factoring x²+4x+3=0(x+3) (x-1)=0x+3=0 / x+1=0x=-3 / x=-1
Answer:
x=-1 ; x=-3 omg sana ma appreciate mo effort ko! chawot lang hehe
Step-by-step explanation:
x=−b±√b^2−4ac/2a
x=−(4)±√(4)^2−4(1)(3)/2(1)
x=-4±√16-12/2
x=−4±√4/2
x=-4+2/2=-2/2=-1
x=-4-2/2=-6/2=-3
x=−1 or x=−3
11. What is degree of;1. (x²-4x+13)(x-5)³=02.(x+1)⁵(x-1)²=03.(x²+4)(x-3)³=04.(x-√2)⁶(x+√2)⁶ x⁴=0What is the real roots of an equation;1. (x²-4x+13)(x-5)³=02.(x+1)⁵(x-1)²=03.(x²+4)(x-3)³=04.(x-√2)⁶(x+√2)⁶ x⁴=0What is the number of real roots;1. (x²-4x+13)(x-5)³=02.(x+1)⁵(x-1)²=03.(x²+4)(x-3)³=04.(x-√2)⁶(x+√2)⁶ x⁴=0Pasagut mga idle...Brainliestt ko Makatama
The degree of the following is 3, 5, 3, and 6, respectively.
(x²-4x+13)(x-5)³=0 (x+1)⁵(x-1)²=0(x²+4)(x-3)³=0(x-√2)⁶(x+√2)⁶ x⁴=0As for the roots,
The equation (x²-4x+13)(x-5)³=0 only has 5 as its real root. The values of x of the quadratic equation are imaginary. Thus, the quantity has no roots, only (x-5)³.As for the equation (x+1)⁵(x-1)²=0, the roots are 1 and -1.For (x²+4)(x-3)³=0, the roots are 2 and 3.And for the equation (x-√2)⁶(x+√2)⁶ x⁴=0, the roots are positive and negative √2 and 0.What is a degree?
The degree is referred to the greatest or highest power that is raised in the equation. For instance, in equation number one, the exponents of the quantities are 1 and 3. 3 is greater than one. Thus, the degree of the equation is 3 and the same rule goes for the rest of the items.
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12. Determine the real root of each equation 1. x + 3 = 0 2. x - 2 = 0 3. x ( x-4) = 0 4. (x+1) (x-3)=0
Answer:
0
Step-by-step explanation:
0
is it answer Im really bad at math
13. are the solutions of x-4=0 and x-3=0 the same as the solutions of (x-4) (x-3)=0? why?
Answer:
Yes
Step-by-step explanation:
(x-4)(x-3)=0 We use the zero product property
x-4=0 x-3=0 Solve the resulting linear equation
x= 4 x=3
14. Give real roots of equation1. (x –3) (x+5) = 0 2. x–13= 0 3. (x +4) (x - 1)³= 0 4. (x–1)²= 0 5. (x + 2) (x +1) (x–3= 0 6.(x+5)²(x–2)³(x+1)=0 7.(x–3)³=0
Answer:
Step-by-step explanation:
pa brainliest po tapoos install nyo po ung photimath sana makatulong po
15. Activity 4: Determine the real root(s) of each equation.1. x-2=02. x + 3 = 03. x(x-4) = 04. (x-4)(x-3) = 05. x(x-9)(2x + 1) = 0LOL
Answer:
2
-3
0 and 4
3 and 4
0,9 and -1/2
16. Give the Number of roots and The Degree1. (x –3) (x+5) = 0 2. x–13= 03. (x +4) (x - 1)³= 0 4. (x–1)²= 05. (x + 2) (x +1) (x–3= 06.(x+5)²(x–2)³(x+1)=07.(x–3)³=0
Answer:
1. (x5) (x 3)
2.(x+5) (x+6)
3.(x+5) (x+2)
4.(x+3) (x+8)
5.(x+8) (x+10)
6.( x+8) (x+7)
7.( - 3) (- 4)
Step-by-step explanation:
CARRY ON LEARNING
PA BRAILIEST NARIN PO
REPORT ME IF WRONG
17. By Factoring1. (x+4) (x+3) =02.(x-3) (x+8) =03.(x-7) (x+7) =04. x (x+8) =05.(2x+7) (2x-7) =0
1. x² 122. x² -243. x² - 495. 2x² - 49
18. Activity 4: Determine the real root(s) of each equation.1. x - 2 = 02. x + 3 = 03. X( X – 4) = 04. (x - 4)(x – 3) = 05. x² ( x – 9)(2x + 1) = 0
1. X-2=0
X=2
2. X+3=0
X=-3
3. X(x-4) =0
X=0, x=4
4. (x-4)(x-3) = 0
X = 4, x = 3
5. X^2(x-9)(2x+1)=0
X=0, x=9, x= 1/2
19. 1. (x + 1)²(x - 5) = 012.8-8=03. (x + 2)(x - 2) = 04. (x-3)(x + 1)(x - 1) = 05. x(x - 4)(x + 5)(x - 1) = 06.(x - 1)(x-3) = 07. (x2 - 4x + 13)(x - 5) = 08. (x + 1)(x - 1)9. (x2 + 4)(x - 3) = 010. (x - 2)(x+ 2) = 0
Answer:
1.x=-1 x=5
2.0=0 (true)
3.x=±2
4.x=3 x=-1 x=1
5.x=0 x=4 x=-5 x=1
6.x=1 x=3
7.x=5
8.x²-1
9.x=3
10.x=±2
Step-by-step explanation:
solution:
1.(x+1)² (x-5)=0
x+1=0. x-5=0
x=-1. x=5
2.8-8=0
0=0 (true)
3.(x+2)(x-2)=0
x²-4=0
x²=4
x=±2 (two real solution x=2 x=-2)
4.(x-3)(x+1)(x-1)
x-3=0
x=3
x+1=0
x=-1
x-1=0
x=1
5.x(x-4)(x+5)(x-1)=0
x=0
x=0
x-4=0
x=4
x+5=0
x=-5
x-1=0
x=1
6.(x-1)(x-3)=0
x-1=0
x=1
x-3=0
x=3
7.(x²-4x+13)(x-5)=0
x²-4x+13=0
x€r
x-5=0
x=5
8.(x+1)(x-1)
=x²-1
9.(x²+4)(x-3)
x²+4=0
x€r
x-3=0
x=3
10.(x-2)(x+2)=0
x-2=0
x=2
x+2=0
x=-2
x=±2 (two real solution)
20. (x+3)(x + 4) = 0[tex](x + 3)( \times + 4) = 0[/tex](×+3)(×+4)=0
Answer:
hope this helps, thank you
21. 1. Determine the real root(s) of each equation.1. x - 2 = 02. x + 3 = 03. x (x - 4) = 04. (x + 3)(x - 4 ) = 05. (x-2)(x + 1)(x + 10 ) = 0
Answer:
1. the root is 2
2. the root is -3
3. the roots are 0 and 4
4. the roots are -3 and 4
5. the roots are 2, -1 and -10
Step-by-step explanation:
equate the eguation into 0 to get the root/s
1. x-2=0
x= 2
2. x+3=0
x= -3
3. x(x-4)=0
x=0 x-4=0
x=4
4. (x+3) (x-4)=0
x+3=0 x-4=0
x= -3 x= 4
5.(x-2)(x + 1)(x + 10 ) = 0
x-2=0 x+1=0 x+10=0
x= 2 x= -1 x= -10
22. 1. X-2=02. x + 3 = 03. x(x – 4) = 04. (x + 1)(x - 3) = 05. x + x-2=06. *(x- 9)(2x + 1) = 07. (x + 4)(x - x + 3) = 08. 2x(x - 36) = 09. (X + 8)(x-7)(x - 2x + 5) = 010. (3x + 1)(x + 7)(x-2)* = 0
Step-by-step explanation:
x=2
1. 2-2=0
2. x= -3
-3+3=0
3. x= -4
x(-4-4)=0
x(-8) =0
4. x+1=0. x-3=0
x=-1. x= 3
-1+1=0. 3-3=0
(0x0) = 0
axb=0
either a, b, or both must be zero so that x will be equate to zero.
23. Determine the real root(s) of each equation.x - 2 = 0x + 3 = 0x( x - 4) = 0(x-4)(x - 3) = 0x( x - 9)(2x + 1) = 0
ayan sagot di ko na magawa yung iba
24. roperty1. (x + 3)(x - 2)(x + 1)(x - 1) = 02.(x + 5)(x - 5)(x + 5)(x - 1) = 03.(x+4)*(x-3) = 04.x(x - 3)*(x + 6)2 = 05. x²(x - 9)=0
Answer:
1. x⁴+x³-7x²-x+6 or x1(sa ibaba po nang x ilagay Yong 1)=-3,x2(ganunn din po Ang 2)=-1,x3(same din sa 3)=1,x4(same din sa 4)=2
2.x⁴+4x³-30x²-100x-125 or x1=-5,x2=1,x3=5
(same din po sa number 1)
5.x3-9x²
or
x1=0,x2=9 (taka note po same instructions po sa number 1 and 2)
Yan Lang po kaya ko..Sana makatulong..God blessed!
25. Determine the real roots of each equation 1 x-2=02.x+3=03.x(x-4)=04.(x-4)(x-3)=05.x^2(x-9)(2x+1)=0
Answer:
1. x=2
2.x+3
3.x=4
4.x²=6
5.2Hx⁴ - 18Hx³
Step-by-step explanation:
yan tamang sagot sana makatulong
26. 1.(X-3)(X-4)=02.(3X-4)(X+5)(X-4)=03.(X+3)²(X-2)³(X-1)=0
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:1.)\:\:x\in\{3,4\} [/tex]
[tex]\qquad \tt \rightarrow \:2.)\;\:x\in\{-5,4/3,4\} [/tex]
[tex]\qquad \tt \rightarrow \:3.)\:\:x\in\{-3,1,2\} [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex] \textsf{1.) solve for x ; (x - 3)(x - 4) = 0} [/tex]
[tex]\qquad \sf \dashrightarrow \: (x - 3)(x - 4) = 0[/tex]
[tex]\textsf{For the Left side of the equation to be 0,} [/tex][tex] \textsf{there are two possibilities ;} [/tex]
[tex] \textsf{Case : 1.) (x - 3) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: x = 3[/tex]
[tex] \textsf{Case : 2.) (x - 4) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: x = 4[/tex]
[tex] \textsf{So, possible values of x are 3 and 4 } [/tex]
____________________________________
[tex] \textsf{2. Solve for x ; (3x - 4)(x + 5)(x - 4) = 0} [/tex]
[tex]\qquad \sf \dashrightarrow \: (3x - 4)(x + 5)(x - 4) = 0[/tex]
[tex] \textsf{For the left side of the equation to be 0, } [/tex][tex] \textsf{there are total three possibilities ;} [/tex]
[tex] \textsf{Case : 1.) (3x - 4) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: 3x = 4[/tex]
[tex]\qquad \sf \dashrightarrow \: x = \dfrac{4}{3} [/tex]
[tex] \textsf{Case : 2.) (x + 5) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: x = - 5[/tex]
[tex] \textsf{Case : 3.) (x - 4) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: x = 4[/tex]
[tex] \textsf{So, possible values of x are : 4/3 , -5 and 4 } [/tex]
____________________________________
[tex] \textsf{3. Solve for x ; (x + 3)²(x - 2)³(x - 1) = 0} [/tex]
[tex] \textsf{For the left side of the equation to be 0, } [/tex][tex] \textsf{there are total three possibilities ;} [/tex]
[tex] \textsf{Case : 1.) (x + 3)² = 0 ; that is (x + 3) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: x = - 3[/tex]
[tex] \textsf{Case : 2.) (x - 2)² = 0 ; that is (x - 2) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: x = 2[/tex]
[tex] \textsf{Case : 3.) (x - 1) = 0} [/tex][tex]\qquad \sf \dashrightarrow \: x = 1[/tex]
[tex] \textsf{So, possible values of x are : -3 , 2 and 1} [/tex]
27. 2. X-8 = 03. (x + 2)(x - 2) = 04. (x - 3)(x + 1)(x - 1) = 05. x(x - 4)(x + 5)(x - 1) = 06. (x - 1)(x - 3) = 07. (x2 - 4x + 13)(x - 5)2 = 08. (x + 1)*(x - 1)2 =09. (X2 + 4)(x - 3)2 = 0x* = 010. (x-12)*(x+13)*x* =
Answer:
try ko po
3.)x²-4=0
Step-by-step explanation:
(x+2) (x-2)=0
x²-2x+2x-4=0
x²-4=0
28. (x+12)(x - 9) = 04) x(x + 2)(3x - 4) = 02) x²(x-1) = 05) (x - 1)(x - 4) = 03) (2x + 3)(x-2)(x-4) = 0with solution please
Answer:
1. (x+12)(x - 9) = 0
x^2 - 9x + 12x - 108 = 0
x^2 + 3x - 108 = 0
4) x(x + 2)(3x - 4) = 0
(x^2 + 2x) (3x - 4) = 0
3x^3 - 4x^2 + 6x^2 - 8x = 0
3x^3 + 2x^2 - 8x = 0
2) x²(x-1) = 0
x^3 - x^2 = 0
5) (x - 1)(x - 4) = 0
x^2 - 4x - x + 4 = 0
x^2 - 5x + 4 = 0
3) (2x + 3)(x-2)(x-4) = 0
(2x^2 - 4x + 3x - 6)(x-4) = 0
(2x^2 - x - 6)(x-4) = 0
2x^3 - 8x^2 - x^2 + 4x - 6x + 24 = 0
2x^3 - 9x^2 - 2x + 24 = 0
.just remind me if i'm wrong.
.sana makatulong po ang sagot ko.
29. A Solve the following quadratic equations1. (X - 5)(x + 1) = 02. (x + 4)(x + 3) = 03. (x-7)x=04 (x + 10)(x-3) = 05. (2x - 7)(x-4) = 06. (3x - 4)(2x + 9) = 0
1.X²-4X-5
2.X²+7X+12
4.X²+7X-30
5.2X²-15x+28
6.6x²+35x-36
Answer:
(simplified)
1.x²-4x-5
2.x²+7x+12
3. x²-7x
4. x²+7x-30
5. 2x²-15x+28
6. 6x²+19x-36
Step-by-step explanation:
use Foil method(First, outside, inside, last)
example:
1. (x-5)(x+1)
multiply first= x(x)
outside= x(1)
inside= -5(x)
last= -5(1)
so you can form
x²+x-5x-5
simplify simply by adding the ones with the aame variables(a, b, c and etc) and with the same exponents (²,³,⁴...)
so you can get x²-4x-5
(ask me if you still have confusions! ^-^)
30. Activity 4: Determine the real root(s) of each1. x - 2 = 02. x + 3 = 03. x( x - 4) = 04. (x-4)(x - 3) = 05. x² ( x -9)(2x + 1) = 0
Answer:
1.x=2
2.x=-3
3.x=0,x=4
4.x=3,x=4
5.x=-1/2,x=0,x=9
